Moment of Inertia Calculator
Calculate moment of inertia for solid cylinders, hoops, spheres, rods, and rectangular plates, and apply the parallel-axis theorem for any offset axis.
Moment of Inertia Calculator
Moment of inertia is the rotational analogue of mass. Mass tells you how strongly an object resists being pushed into straight-line motion; moment of inertia tells you how strongly the same object resists being spun up, slowed down, or held against a twisting load. Every rotational problem you will ever solve — a flywheel storing energy, a door swinging on its hinges, a robotic arm slewing into position, a gymnast tucking into a somersault — depends on this single quantity.
The reason moment of inertia deserves its own calculator is that it cannot be read off a label. Mass is a single number you can measure on a scale. Moment of inertia depends on how that mass is arranged relative to the axis you have chosen. Take two objects with identical mass and identical outer radius: a thin hoop and a solid sphere. The hoop has a moment of inertia of 2.5 kg·m² and the sphere only 1 kg·m² for the same 10 kg and the same 0.5 m radius. Nothing about their mass or size differs. Only the distribution does — and distribution is exactly what determines how hard they are to rotate.
This calculator handles the five shapes that cover the overwhelming majority of textbook and engineering problems: solid cylinder or disk, thin hoop or ring, solid sphere, thin rod rotating about its center, and rectangular plate rotating about its central axis. Each one asks only for mass and the relevant dimensions. An optional axis offset field then lets you move the rotation axis away from the center of mass and applies the parallel-axis theorem for you — which is the difference between a correct answer and an answer that is wrong by several hundred percent on real hardware.
Moment of inertia pairs naturally with the neighbouring mechanics tools. The Torque Calculator supplies the twisting load that the moment of inertia resists, the Force Calculator explains where that load comes from, the Centripetal Force Calculator covers the inward force needed to keep a mass on a circular path, and the Kinetic & Potential Energy Calculator tracks the energy stored in a spinning body. Together they describe rotating systems from cause to effect. [openstax-rotational-inertia]
The calculator asks for three things: the shape you are analysing, the mass in kilograms, and the dimensions of that shape in meters. Pick the shape from the selector, enter mass and dimensions, and the results update automatically. If the rotation axis does not pass through the center of mass, enter the perpendicular distance between the two axes in the optional Axis Offset field.
The outputs are: the Moment of Inertia about your chosen axis, the moment of inertia About the Center of Mass, the Parallel-Axis Term (the extra inertia contributed by the shift, shown only when an offset is present), and the Radius of Gyration, which condenses the whole distribution into a single effective distance.
Example 1: A solid cylinder
A solid steel disk of 10 kg and 0.5 m radius spins on its own central axis.
- Select Solid cylinder
- Enter Mass: 10 kg
- Enter Radius: 0.5 m
- Leave Axis Offset blank
The calculator returns 1.25 kg·m². Doubling the radius to 1 m would quadruple the result to 5 kg·m², because radius enters the formula squared while mass enters linearly. That squared dependence is the single most important fact about rotational inertia: size matters far more than weight.
Example 2: A hoop and a sphere with identical mass and radius
Now switch the shape selector without touching the numbers. A thin hoop of 10 kg and 0.5 m radius gives 2.5 kg·m². A solid sphere of 10 kg and the same 0.5 m radius gives 1 kg·m².
Same mass, same outer size, and one object is two and a half times harder to spin up than the other. In the hoop, every kilogram sits at the full radius of 0.5 m. In the sphere, mass is packed toward the center where its distance from the axis is small. This is the clearest demonstration available of why the shape selector exists at all. [khan-rotational-inertia]
Example 3: A thin rod about its center
A 10 kg bar of length 2 m rotates about an axis through its midpoint, like a propeller or a metronome.
- Select Thin rod (center)
- Enter Mass: 10 kg
- Enter Length: 2 m
The result is 3.333333 kg·m². Note that only the length of the rod enters the formula, not its thickness — the thin-rod model assumes the cross-section is negligible compared with the length.
Example 4: A rectangular plate
A flat panel of 10 kg measuring 1 m by 2 m rotates about a perpendicular axis through its center.
- Select Rectangular plate
- Enter Mass: 10 kg
- Enter Width: 1 m
- Enter Height: 2 m
The calculator returns 4.166667 kg·m². The formula adds the squares of both sides, so a panel that is twice as long in one direction does not have twice the inertia of a square panel — it has 1.25 times as much for these particular dimensions.
Example 5: Moving the axis with an offset
Back to the solid cylinder from Example 1, but now the axis is parallel to the central one and 0.2 m to the side — the same situation as a door panel hanging off its hinge line, or a wheel mounted off-center on a shaft.
- Select Solid cylinder
- Enter Mass: 10 kg
- Enter Radius: 0.5 m
- Enter Axis Offset: 0.2 m
Three results appear. The moment of inertia about the shifted axis is 1.65 kg·m². The parallel-axis term, the contribution of the displacement alone, is 0.4 kg·m². The radius of gyration is 0.406202 m. Notice that the offset term is huge relative to the base value: shifting a compact object 0.2 m sideways added almost a third of its original inertia, because the added term grows with the square of the distance and applies to the entire mass at once. [nasa-angular-motion]
The definition of moment of inertia for a collection of discrete masses is a sum:
For a continuous body, the sum becomes an integral over the mass distribution:
Here I is the moment of inertia in kilogram-meters squared (kg·m²), m is mass in kilograms, and r is the perpendicular distance from each element of mass to the axis of rotation in meters. Read it literally: each speck of mass contributes in proportion to its mass, multiplied by the square of its distance from the axis. Mass sitting twice as far from the axis contributes four times as much. Mass sitting on the axis contributes nothing at all.
The rotational analogy
Moment of inertia is one rung of a complete dictionary that translates linear mechanics into rotational mechanics. Every linear law has a rotational twin, with mass replaced by moment of inertia:
- Mass (m) becomes moment of inertia (I). Both measure resistance to a change in motion, one linear and one angular.
- Force (F) becomes torque (τ). A push becomes a twist.
- Acceleration (a) becomes angular acceleration (α). Straight-line speed-up becomes spin-up.
That mapping turns Newton's second law into its rotational form:
Momentum becomes angular momentum:
And kinetic energy becomes rotational kinetic energy:
The practical consequence is dramatic. Under a fixed torque, doubling the moment of inertia halves the angular acceleration. In the linear world you would need to double the mass to get that effect; in the rotational world you can achieve it without adding a single kilogram, simply by moving the existing mass farther from the axis. This is why an ice skater spins slowly with arms extended and rapidly with arms pulled in, and why engineers designing a flywheel deliberately push mass to the rim. [nasa-angular-motion]
The five shapes
The integral above evaluates to a clean expression for every common geometry. For a solid cylinder or disk:
For a thin hoop or ring, where all the mass sits at the same radius:
For a solid sphere:
For a thin rod rotating about an axis through its center, perpendicular to its length:
And for a rectangular plate rotating about a perpendicular axis through its center, where a and b are the two side lengths (width and height):
Compare the leading fractions: 1, 2/5, 1/2, 1/12. The hoop's fraction of 1 reflects the worst possible distribution — every gram at maximum radius. The rod and plate fractions of 1/12 reflect the best distribution among these five, because a large share of their mass lies close to the axis. Same physics, five different arrangements, and the coefficient alone tells you which one is hardest to spin. [openstax-moment-of-inertia]
The parallel-axis theorem
Every formula above assumes the axis passes through the center of mass. Move the axis and the moment of inertia increases. The parallel-axis theorem quantifies exactly how much:
I_cm is the moment of inertia about a parallel axis through the center of mass, M is the total mass, and d is the perpendicular distance between the two axes. The theorem is remarkable because it is completely independent of the shape: only the total mass and the displacement matter.
A door is the classic real-world case. A door panel hanging on its hinges rotates about an axis at one edge, not through its own center. Treating the panel as a thin rectangular plate and applying the theorem moves the axis from the middle to the edge, roughly quadrupling the effective inertia compared with the same panel pivoting about its center — which is exactly why doors are hinged at the edge, so a small push near the handle still swings a heavy slab.
The theorem also explains a result you may have memorized without seeing why it works. A thin rod about one end has four times the inertia of the same rod about its center:
Substituting the numbers from Example 3 — a 10 kg rod of length 2 m — the center result of 3.333333 kg·m² plus a parallel-axis term of 10 kg·m² gives 13.333333 kg·m² about the end. The displacement term dominates, because the whole rod's mass is treated as concentrated at a distance d of 1 m. [hyperphysics-parallel-axis]
Radius of gyration
When you need to compare objects of different mass, or feed a result into a vibration or pendulum calculation, the radius of gyration is the most useful compact number:
The radius of gyration is the distance from the axis at which the entire mass could be concentrated to produce the same moment of inertia. It converts an abstract distribution into a single intuitive length. For the cylinder of 10 kg and 0.5 m radius, k is 0.353553 m — well inside the rim, because half the material sits closer to the axis than that. For the hoop, k equals the radius exactly, since all the mass genuinely is at the rim.
The table below lists the five shapes supported by the calculator, each evaluated with a mass of 10 kg and the dimensions used in the examples above, plus two common textbook cases that show how much the axis choice matters.
| Solid cylinder (about central axis) | ½ M R² | 10 | R = 0.5 m | 1.25 |
| Thin hoop / ring | M R² | 10 | R = 0.5 m | 2.5 |
| Solid sphere | ⅖ M R² | 10 | R = 0.5 m | 1 |
| Thin rod (center) | 1/12 M L² | 10 | L = 2 m | 3.333333 |
| Rectangular plate (center) | 1/12 M (a² + b²) | 10 | 1 m × 2 m | 4.166667 |
| Thin spherical shell | ⅔ M R² | 10 | R = 0.5 m | 1.666667 |
| Thin rod (one end) | ⅓ M L² | 10 | L = 2 m | 13.333333 |
Reading down the table, the pattern is entirely about where the mass lives. The solid sphere at 1 kg·m² is the most compact of the round shapes because its density is highest at the center. The hoop at 2.5 kg·m² is the least compact, with the sphere-versus-hoop gap being a factor of 2.5 for identical mass and radius. The hollow shell at 1.666667 kg·m² sits between them: it is hollow, but its mass is spread over a surface rather than concentrated in a thin ring. Finally, the rod about one end at 13.333333 kg·m² is more than four times its own center value, and is the largest figure in the table despite a modest 10 kg mass — a direct illustration of the parallel-axis theorem at work. [wikipedia-moment-of-inertia]
1. Ask where the mass sits before adding mass. The instinct when a mechanism feels sluggish is to reach for a bigger motor. But if the load is a hoop, a hollow tube, or a rim-weighted wheel, moving the material toward the axis can cut the inertia dramatically at zero cost in strength. Lightening the rim of a flywheel is often more effective than upgrading the drive.
2. Push mass outward to store energy, inward to spin fast. A flywheel energy-storage system wants its mass at the maximum radius, which is why flywheels are thick-rimmed rather than solid disks. A figure skater doing a spin wants the opposite and pulls their arms in. Both are applying the same squared-distance term in opposite directions.
3. Fix the axis before you compute. Moment of inertia is meaningless without a stated axis. A rod's value is 3.333333 kg·m² about its center and 13.333333 kg·m² about its end — a fourfold difference between two answers that are both correct for their own question. Write down the axis line first, then choose the formula.
4. Use the parallel-axis theorem instead of re-integrating. For a robot arm, a pendulum bob on an offset bracket, or a door panel, you rarely need calculus. Take the tabulated center-of-mass value from the reference table and add the product of mass and the square of the offset distance. The calculator's Axis Offset field does this in one step.
5. Compare objects with the radius of gyration, not raw inertia. A 50 kg wheel with an inertia of 5 kg·m² has a radius of gyration of about 0.32 m, so it behaves like a 50 kg point mass on a 0.32 m arm. Expressing inertia this way lets you sanity-check a design: if the radius of gyration comes out larger than the physical part, something in the input is wrong.
6. Watch the units, especially when converting from centimeters. The formulas only produce kg·m² when mass is in kilograms and every length is in meters. A radius entered as 50 instead of 0.5 inflates the answer by a factor of 10,000. If a result looks wildly wrong, the unit conversion is the first thing to check — not the shape. [lumen-rotational-inertia]
Rigid bodies with uniform density. Every formula here assumes the object does not deform and that its density is constant. Real parts have bosses, holes, weld beads, and material gradients. A cast-iron flywheel with a thick rim approximated as a uniform disk can be off by a large margin; treat such parts as a sum of simple shapes instead.
The axis must be a principal or symmetry axis. The tabulated expressions apply to rotation about a symmetry axis of the body. For an arbitrary tilted axis you need the full inertia tensor, and the parallel-axis theorem cannot be used to rotate an axis — it only shifts a parallel one. Off-axis rotation of an asymmetric body can produce wobble and bearing loads that this calculator does not predict.
Thin-part approximations. The thin rod formula ignores the cross-section, and the thin plate formula ignores thickness. Both are accurate when the neglected dimension is small compared with the length scale of interest. A stubby bar or a thick slab needs a full three-dimensional treatment.
Composite bodies are not handled directly. A single call returns one shape. An assembly such as a wheel with a hub, spokes, and a rim must be decomposed into parts, each computed about the same axis, and then added — remembering to shift the center-of-mass values of the off-axis parts with the parallel-axis theorem before summing.
Inertia alone does not describe motion. Moment of inertia says how strongly a body resists angular acceleration. It says nothing about friction in the bearings, aerodynamic drag, or the torque available from a motor, all of which determine what actually happens. For dynamics you also need the torque and angular acceleration relationship, as covered by the Torque Calculator, and for the translational side of a rolling or orbiting system, the Momentum Calculator and Force Calculator.
No measurement uncertainty is propagated. The calculation is exact arithmetic on the numbers you type. If your mass came from a bathroom scale and your radius from a tape measure, the true uncertainty is in the inputs, and a result quoted to six decimals is not six decimals accurate. Round the output to match the precision of your measurements.
- ❓ What is moment of inertia in simple terms?
- ✅ Moment of inertia is the rotational equivalent of mass. Mass measures how hard it is to change an object's straight-line speed, and moment of inertia measures how hard it is to change its spinning speed. It depends on the total mass and, just as importantly, on how far that mass sits from the axis of rotation.
- ❓ Why is moment of inertia not simply the mass?
- ✅ Because rotational resistance depends on distance from the axis, not just on the amount of matter. Each element of mass contributes in proportion to the square of its distance from the axis, so the same kilogram contributes four times as much when it is twice as far out. Mass alone cannot capture that geometric information.
- ❓ What is the difference between inertia and moment of inertia?
- ✅ Inertia in everyday language is the general tendency of an object to resist changes in its motion, and for translation it is measured by mass. Moment of inertia is the specific rotational quantity, measured in kilogram-meters squared, that plays the role of mass in all the equations of rotation. The word moment here means weighted by distance, not a moment in time.
- ❓ Why does a hoop have 2.5 times the moment of inertia of a solid sphere with the same mass and radius?
- ✅ In a thin hoop every kilogram sits at the full radius, so each one contributes its mass times the radius squared. In a solid sphere the material is concentrated toward the center, where the distance from the axis is small, so most of the mass contributes far less. The ratio of the coefficients confirms it: the hoop coefficient is 1 and the solid sphere coefficient is 2 divided by 5.
- ❓ When can I use the parallel-axis theorem?
- ✅ Whenever your axis of rotation is parallel to an axis through the center of mass and you know the center-of-mass moment of inertia. Add the total mass multiplied by the square of the perpendicular distance between the two axes. The theorem does not work for axes that are tilted relative to each other, only for parallel shifts.
- ❓ What is the radius of gyration?
- ✅ The radius of gyration is the distance from the axis at which the entire mass could be concentrated, as a point, to give the same moment of inertia as the real object. It is calculated as the square root of moment of inertia divided by mass. It is useful for comparing parts of different mass and for feeding inertia values into vibration and pendulum formulas.
- ❓ Does the axis of rotation have to pass through the center of mass?
- ✅ No, and in real machinery it often does not. A door rotates about its hinge edge, a pendulum about a pivot at the top of its rod, and a swing arm about a fixed bearing. When the axis is offset, use the parallel-axis theorem to shift the center-of-mass value to your actual axis, which is what the Axis Offset field does.
- ❓ How is moment of inertia related to torque?
- ✅ They are linked by the rotational form of Newton's second law: torque equals moment of inertia multiplied by angular acceleration. For a given applied torque, a larger moment of inertia produces a smaller angular acceleration, exactly as a larger mass produces a smaller linear acceleration for a given force. This is the direct translational analogy.
- ❓ Can a hollow object have a larger moment of inertia than a solid one of the same mass?
- ✅ Yes, and this is the normal case. Removing material from the center and placing it near the rim increases the average distance of the mass from the axis, which increases moment of inertia even though the total mass is unchanged. A hollow tube resists rotation more than a solid rod of the same mass and outer radius.
- ❓ Which moment of inertia applies to a door swinging on its hinges?
- ✅ The door rotates about an axis at one edge rather than through its own center, so you take the center-of-mass value for a rectangular plate and add the parallel-axis term for the offset. That increases the effective inertia several-fold compared with the same panel pivoting about its middle, which is why door handles are placed far from the hinge.
- ❓ Why does a figure skater spin faster when pulling their arms in?
- ✅ Angular momentum, equal to moment of inertia times angular velocity, is conserved when no external torque acts. Pulling the arms in moves mass closer to the axis, which reduces the moment of inertia. To keep the product of inertia and angular velocity constant, the angular velocity must increase, and the skater spins faster.
- ❓ What are the units of moment of inertia?
- ✅ The SI unit is kilogram-meter squared, written kg m squared. It comes directly from the definition: mass in kilograms multiplied by distance from the axis in meters, squared. In imperial engineering work you may encounter slug-feet squared or pound-feet-second squared, but this calculator reports SI values only.
References
- [1]OpenStax. (2020). Dynamics of rotational motion: Rotational inertia. College Physics 2e.
- [2]OpenStax. (2016). Moment of inertia and rotational kinetic energy. University Physics Volume 1.
- [3]HyperPhysics. (n.d.). Moment of inertia. Georgia State University.
- [4]HyperPhysics. (n.d.). Parallel axis theorem. Georgia State University.
- [5]Wikipedia. (n.d.). Moment of inertia.
- [6]Lumen Learning. (n.d.). Dynamics of rotational motion: Rotational inertia.
- [7]Khan Academy. (n.d.). Rotational inertia.
- [8]NASA Glenn Research Center. (n.d.). Angular displacement, velocity, and acceleration.
Last updated: October 20, 2026
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